y-3/y^2-y+3/2y

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Solution for y-3/y^2-y+3/2y equation: 


D( y )

y^2 = 0

y^2 = 0

y^2 = 0

1*y^2 = 0 // : 1

y^2 = 0

y = 0

y in (-oo:0) U (0:+oo)

y-y+(3/2)*y-(3/(y^2)) = 0

y-y+(3/2)*y-3*y^-2 = 0

3/2*y-3*y^-2 = 0

3*y*(1/2-y^-3) = 0

-1*y^-3 = -1/2 // : -1

y^-3 = 1/2

-3 < 0

1/(y^3) = 1/2 // * y^3

1 = 1/2*y^3 // : 1/2

2 = y^3

y^3 = 2 // ^ 1/3

y = 2^(1/3)

3*y = 0

3*y = 0 // : 3

y = 0

y in { 0} 

y = 2^(1/3)

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